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How to solve this Geometry problem?; Help please?
Topic Started: Feb 1 2006, 10:20 PM (548 Views)
Kyman_33
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Ok, we are supposed to find the lengths for the altitude of the two triangles (the lenghts of c and d). From all that info we are supposed to be able to figure it out.

One more piece of info is that, the scale factor is 3/4. (The triangles were said to be similar, but I don't have the rest of the specifics, just trust me its .75 because the sides match up different then it looks because of prior specifications. 15/20, 9/12, and 12/16)

Our teacher was trying to solve it with us in class, but no one had any idea of even where to start so she got mad and just skipped it. She has no patience.

I was wondering if any of you would know how?

Thanks a bunch,

-Kyle
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Lastscionz
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.-.
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;)
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soGONE
dharma
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Eh, this is beyond my knowledge of Geometry sorry :/
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Ross
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After clarification by the topic starter, I am reopening this topic.
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Remzo
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Isnt this trigonometry? And It needs a angle to be able to be solved. But If I had the angle I needed, I would just follow through with the cosine law which is SAS.
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SyKo
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aka godman123
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D would be AB / one half right? So that would be something like 7.x. C would be 10.

I think.

:ermm:
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Postulate
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You're the point
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SyKo
Feb 1 2006, 10:07 PM
D would be AB / one half right? So that would be something like 7.x. C would be 10.

I think.

:ermm:

That would work if we were dealing with a right triangle, but there's no evidence of that.
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Curry
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Prismatic
Feb 2 2006, 01:09 AM
SyKo
Feb 1 2006, 10:07 PM
D would be AB / one half right? So that would be something like 7.x. C would be 10.

I think.

:ermm:

That would work if we were dealing with a right triangle, but there's no evidence of that.

Yes there is. The sides are sides of a right triangle. The Pythagorean Theorem.
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Postulate
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You're the point
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Vulcan
Feb 2 2006, 03:29 AM
Prismatic
Feb 2 2006, 01:09 AM
SyKo
Feb 1 2006, 10:07 PM
D would be AB / one half right? So that would be something like 7.x. C would be 10.

I think.

:ermm:

That would work if we were dealing with a right triangle, but there's no evidence of that.

Yes there is. The sides are sides of a right triangle. The Pythagorean Theorem.

Right, I overlooked that.

Okay, since each triangle's hypotenuse is the square of the sum of the sqaures of the bases, then by the PT both are right triangles. Since you know that, you can colcude that the altitudes of the triangle are half the lengths of the hypotenuse. So godman was right: the lengths are 7.5 and 10.
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j71
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Its triganometry.
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the format
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Liberate says: format your legs are so hawt
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j71
Feb 2 2006, 04:43 PM
Its triganometry.

No that's what we learn in Geometry.
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j71
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Thats trig up here.
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Curare
laaaaaaax.
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j71
Feb 2 2006, 07:30 PM
Thats trig up here.

No, it's not.
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j71
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Yes.. It is.. I just wrote my exam on Monday.
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Drew
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That scares me and gives me headaches. Good luck.

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